Law of Sines: Solving Any Triangle
The Law of Sines relates sides and opposite angles in any triangle. See when to apply it, how to handle the ambiguous case, and practical examples.
Renato Freitas
Updated on May 5, 2026
Statement and geometric intuition
The Law of Sines states that in any triangle with sides a, b, c and opposite angles A, B, C respectively: a / sin A = b / sin B = c / sin C.
This constant ratio equals the diameter of the circumscribed circle (the circle passing through all three vertices), providing a beautiful geometric interpretation: the larger the side, the larger the opposite angle — and the Law of Sines quantifies exactly that relationship.
The intuition is direct: if angle A is large, side a (facing it) is also large. The law tells us in what proportion these growths are related, allowing us to calculate the unknown from the known.
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When to use the Law of Sines
The Law of Sines applies when you know: (AAS) two angles and any side — you can find the other two sides; (ASA) two angles and the side between them — same; (SSA) two sides and the angle opposite one of them — a situation that requires special attention, the ambiguous case.
It does not apply directly when you know only the three sides (SSS) or two sides and the angle between them (SAS) — in those cases, the Law of Cosines is the right tool.
A common mistake is trying to use the Law of Sines when there is no complete pair (side + opposite angle). Always verify that you have at least one side-angle pair before applying the formula.
- AAS: two angles + non-included side → use Law of Sines
- ASA: two angles + included side → use Law of Sines
- SSA: two sides + opposite angle → Law of Sines, but check the ambiguous case
- SAS or SSS → prefer the Law of Cosines
Solving a triangle step by step
Example AAS: A = 40°, B = 75°, a = 10. First, C = 180° − 40° − 75° = 65°. Then, b / sin 75° = 10 / sin 40°, so b = 10 × sin 75° / sin 40° ≈ 10 × 0.966 / 0.643 ≈ 15.02. Similarly, c = 10 × sin 65° / sin 40° ≈ 14.10.
The process has three steps: (1) calculate the missing angle using A + B + C = 180°; (2) set up the Law of Sines ratios; (3) isolate the unknown side or angle and calculate.
Always verify that the sum of the angles found equals 180°. Small rounding errors can accumulate, so keep at least 4 decimal places in intermediate calculations.
The ambiguous case SSA
In the SSA case (knowing a, b, and A), there may be zero, one, or two solutions for the triangle. This happens because, when drawing side a from vertex B with a fixed length, the far end may not reach side b (no solution), touch it at a single point (unique solution), or cross it at two points (two solutions).
Practical rule: if A is obtuse (greater than 90°), a solution exists only if a > b. If A is acute, compare a with b × sin A (the triangle's altitude): if a < altitude, no solution; if a = altitude, right triangle; if altitude < a < b, two solutions; if a ≥ b, unique solution.
When there are two solutions, the two possible angles for B are supplementary: B₁ and B₂ = 180° − B₁. Each produces a different triangle. In practical problems, context usually indicates which one makes sense.
Practical applications
In surveying, the Law of Sines allows measuring inaccessible distances. Measure two points A and B on the ground (baseline), observe the angle to an inaccessible point C from each end, and calculate the distance AC or BC.
In navigation, pilots and sailors triangulate positions: they observe two known landmarks and measure the bearing angles to determine the exact position of the vessel.
The law also appears in physics (geometric optics, analysis of forces in equilibrium) and in computer graphics, for interpolating positions in three-dimensional scenes.
Frequently asked questions
Does the Law of Sines work for right triangles?
Yes, it works for any triangle, including right triangles. For a right triangle with C = 90°, the formula simplifies because sin 90° = 1: a/sinA = b/sinB = c/1 = c. This is equivalent to the basic ratios sin A = a/c and sin B = b/c.
Why does the ratio equal the diameter of the circumscribed circle?
It follows from the Inscribed Angle Theorem: an inscribed angle is half the central angle that subtends the same arc. From this, a = 2R sin A, where R is the circumradius. Therefore a/sin A = 2R, a constant for the triangle.
How do I know if a problem has the ambiguous case?
The ambiguous case occurs when the given data is SSA: two sides and the angle opposite one of them. If the given angle is opposite the shorter of the two sides, ambiguity is possible. If the given angle is opposite the longer side, the solution is unique (or nonexistent).
Can I use the Law of Sines with angles in radians?
Yes, with no modification to the formula. The sine function accepts both degrees and radians; just make sure the calculator is in the correct mode. The result will be the same.
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